Base | Representation |
---|---|
bin | 1000110010100010001… |
… | …1000100000001111111 |
3 | 112102202201220212220011 |
4 | 2030220203010001333 |
5 | 4433224024314201 |
6 | 153211554404051 |
7 | 13624010655103 |
oct | 2145043040177 |
9 | 472681825804 |
10 | 151004135551 |
11 | 59049997045 |
12 | 25322b90627 |
13 | 11316606ac9 |
14 | 7446c97903 |
15 | 3ddbd2b151 |
hex | 23288c407f |
151004135551 has 4 divisors (see below), whose sum is σ = 152499226104. Its totient is φ = 149509045000.
The previous prime is 151004135543. The next prime is 151004135567. The reversal of 151004135551 is 155531400151.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 151004135551 - 23 = 151004135543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (151004135591) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 747545125 + ... + 747545326.
It is an arithmetic number, because the mean of its divisors is an integer number (38124806526).
Almost surely, 2151004135551 is an apocalyptic number.
151004135551 is a deficient number, since it is larger than the sum of its proper divisors (1495090553).
151004135551 is a wasteful number, since it uses less digits than its factorization.
151004135551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1495090552.
The product of its (nonzero) digits is 7500, while the sum is 31.
The spelling of 151004135551 in words is "one hundred fifty-one billion, four million, one hundred thirty-five thousand, five hundred fifty-one".
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