1510124131 has 2 divisors, whose sum is σ = 1510124132. Its totient is φ = 1510124130.

The previous prime is 1510124117. The next prime is 1510124141. The reversal of 1510124131 is 1314210151.

It is a strong prime.

It is an emirp because it is prime and its reverse (1314210151) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1510124131 is a prime.

It is a super-2 number, since 2×1510124131² = 4560949782057010322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1510124099 and 1510124108.

It is not a weakly prime, because it can be changed into another prime (1510124101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 755062065 + 755062066.

It is an arithmetic number, because the mean of its divisors is an integer number (755062066).

Almost surely, 2^1510124131 is an apocalyptic number.

1510124131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1510124131 is an equidigital number, since it uses as much as digits as its factorization.

1510124131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 19.

The square root of 1510124131 is about 38860.3156317599. The cubic root of 1510124131 is about 1147.2838560497.

Adding to 1510124131 its reverse (1314210151), we get a palindrome (2824334282).

The spelling of 1510124131 in words is "one billion, five hundred ten million, one hundred twenty-four thousand, one hundred thirty-one".