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151020351141 = 31138031203359
BaseRepresentation
bin1000110010100110000…
…0111010111010100101
3112102210212102201111120
42030221200322322211
54433242202214031
6153213334124153
713624265542632
oct2145140727245
9472725381446
10151020351141
1159058062060
12253284b0659
1311319a9382a
1474490b9189
153ddd480a96
hex232983aea5

151020351141 has 16 divisors (see below), whose sum is σ = 219723909120. Its totient is φ = 91503342320.

The previous prime is 151020351113. The next prime is 151020351143. The reversal of 151020351141 is 141153020151.

It is a cyclic number.

It is not a de Polignac number, because 151020351141 - 230 = 149946609317 is a prime.

It is a super-3 number, since 3×1510203511413 (a number of 35 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (151020351143) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 476181 + ... + 727178.

It is an arithmetic number, because the mean of its divisors is an integer number (13732744320).

Almost surely, 2151020351141 is an apocalyptic number.

151020351141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

151020351141 is a deficient number, since it is larger than the sum of its proper divisors (68703557979).

151020351141 is a wasteful number, since it uses less digits than its factorization.

151020351141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1207176.

The product of its (nonzero) digits is 600, while the sum is 24.

Adding to 151020351141 its reverse (141153020151), we get a palindrome (292173371292).

The spelling of 151020351141 in words is "one hundred fifty-one billion, twenty million, three hundred fifty-one thousand, one hundred forty-one".

Divisors: 1 3 11 33 3803 11409 41833 125499 1203359 3610077 13236949 39710847 4576374277 13729122831 50340117047 151020351141