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151020354501 = 341864448821
BaseRepresentation
bin1000110010100110000…
…0111011101111000101
3112102210212102220010000
42030221200323233011
54433242202321001
6153213334151513
713624265555502
oct2145140735705
9472725386100
10151020354501
1159058064635
12253284b2599
1311319a95213
1474490ba4a9
153ddd481a86
hex232983bbc5

151020354501 has 10 divisors (see below), whose sum is σ = 225598307462. Its totient is φ = 100680236280.

The previous prime is 151020354497. The next prime is 151020354517. The reversal of 151020354501 is 105453020151.

151020354501 is a `hidden beast` number, since 1 + 5 + 1 + 0 + 203 + 5 + 450 + 1 = 666.

151020354501 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 93146429601 + 57873924900 = 305199^2 + 240570^2 .

It is not a de Polignac number, because 151020354501 - 22 = 151020354497 is a prime.

It is a super-3 number, since 3×1510203545013 (a number of 35 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (151020354101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 932224330 + ... + 932224491.

Almost surely, 2151020354501 is an apocalyptic number.

It is an amenable number.

151020354501 is a deficient number, since it is larger than the sum of its proper divisors (74577952961).

151020354501 is an equidigital number, since it uses as much as digits as its factorization.

151020354501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1864448833 (or 1864448824 counting only the distinct ones).

The product of its (nonzero) digits is 3000, while the sum is 27.

Adding to 151020354501 its reverse (105453020151), we get a palindrome (256473374652).

It can be divided in two parts, 151020 and 354501, that added together give a square (505521 = 7112).

The spelling of 151020354501 in words is "one hundred fifty-one billion, twenty million, three hundred fifty-four thousand, five hundred one".

Divisors: 1 3 9 27 81 1864448821 5593346463 16780039389 50340118167 151020354501