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151031205055043 is a prime number
BaseRepresentation
bin100010010101110010110001…
…010100111100101001000011
3201210202102221100201021000222
4202111302301110330221003
5124243443401443230133
61253114435555133255
743545434025122315
oct4225626124745103
9653672840637028
10151031205055043
1144139a79972945
1214b32a38ba422b
136637248a70b61
142941d40d557b5
15126da054a7e98
hex895cb153ca43

151031205055043 has 2 divisors, whose sum is σ = 151031205055044. Its totient is φ = 151031205055042.

The previous prime is 151031205054971. The next prime is 151031205055079. The reversal of 151031205055043 is 340550502130151.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 151031205055043 - 216 = 151031204989507 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 151031205054994 and 151031205055012.

It is not a weakly prime, because it can be changed into another prime (151031205855043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75515602527521 + 75515602527522.

It is an arithmetic number, because the mean of its divisors is an integer number (75515602527522).

Almost surely, 2151031205055043 is an apocalyptic number.

151031205055043 is a deficient number, since it is larger than the sum of its proper divisors (1).

151031205055043 is an equidigital number, since it uses as much as digits as its factorization.

151031205055043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45000, while the sum is 35.

Adding to 151031205055043 its reverse (340550502130151), we get a palindrome (491581707185194).

The spelling of 151031205055043 in words is "one hundred fifty-one trillion, thirty-one billion, two hundred five million, fifty-five thousand, forty-three".