Base | Representation |
---|---|
bin | 1000110010111010000… |
… | …1100101001010000010 |
3 | 112110000201121100220121 |
4 | 2030232201211022002 |
5 | 4433430212111432 |
6 | 153225535530454 |
7 | 13626336203122 |
oct | 2145641451202 |
9 | 473021540817 |
10 | 151104410242 |
11 | 590a0555995 |
12 | 25350689a2a |
13 | 11331315646 |
14 | 745631ac82 |
15 | 3de5a37197 |
hex | 232e865282 |
151104410242 has 4 divisors (see below), whose sum is σ = 226656615366. Its totient is φ = 75552205120.
The previous prime is 151104410213. The next prime is 151104410267. The reversal of 151104410242 is 242014401151.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 148216530121 + 2887880121 = 384989^2 + 53739^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37776102559 + ... + 37776102562.
Almost surely, 2151104410242 is an apocalyptic number.
151104410242 is a deficient number, since it is larger than the sum of its proper divisors (75552205124).
151104410242 is an equidigital number, since it uses as much as digits as its factorization.
151104410242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75552205123.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 151104410242 its reverse (242014401151), we get a palindrome (393118811393).
Subtracting 151104410242 from its reverse (242014401151), we obtain a palindrome (90909990909).
The spelling of 151104410242 in words is "one hundred fifty-one billion, one hundred four million, four hundred ten thousand, two hundred forty-two".
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