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151112052432433 is a prime number
BaseRepresentation
bin100010010110111110000100…
…001101001101111000110001
3201211001011121202022120021201
4202112332010031031320301
5124301304440410314213
61253215530223051201
743554325346363041
oct4226760415157061
9654034552276251
10151112052432433
114417029712a114
1214b46640740b01
136641a616062c1
142945c1046d721
151270b8805b6dd
hex896f8434de31

151112052432433 has 2 divisors, whose sum is σ = 151112052432434. Its totient is φ = 151112052432432.

The previous prime is 151112052432421. The next prime is 151112052432533. The reversal of 151112052432433 is 334234250211151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139648295674944 + 11463756757489 = 11817288^2 + 3385817^2 .

It is a cyclic number.

It is not a de Polignac number, because 151112052432433 - 213 = 151112052424241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 151112052432392 and 151112052432401.

It is not a weakly prime, because it can be changed into another prime (151112052432233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75556026216216 + 75556026216217.

It is an arithmetic number, because the mean of its divisors is an integer number (75556026216217).

Almost surely, 2151112052432433 is an apocalyptic number.

It is an amenable number.

151112052432433 is a deficient number, since it is larger than the sum of its proper divisors (1).

151112052432433 is an equidigital number, since it uses as much as digits as its factorization.

151112052432433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 37.

The spelling of 151112052432433 in words is "one hundred fifty-one trillion, one hundred twelve billion, fifty-two million, four hundred thirty-two thousand, four hundred thirty-three".