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151126433 is a prime number
BaseRepresentation
bin10010000001000…
…00000110100001
3101112101000111022
421000200012201
5302142021213
622555055225
73513360563
oct1100400641
9345330438
10151126433
1178341587
1242741515
1325404833
14160dd333
15d403308
hex90201a1

151126433 has 2 divisors, whose sum is σ = 151126434. Its totient is φ = 151126432.

The previous prime is 151126421. The next prime is 151126439. The reversal of 151126433 is 334621151.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76615009 + 74511424 = 8753^2 + 8632^2 .

It is an emirp because it is prime and its reverse (334621151) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-151126433 is a prime.

It is not a weakly prime, because it can be changed into another prime (151126439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75563216 + 75563217.

It is an arithmetic number, because the mean of its divisors is an integer number (75563217).

Almost surely, 2151126433 is an apocalyptic number.

It is an amenable number.

151126433 is a deficient number, since it is larger than the sum of its proper divisors (1).

151126433 is an equidigital number, since it uses as much as digits as its factorization.

151126433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2160, while the sum is 26.

The square root of 151126433 is about 12293.3491368300. The cubic root of 151126433 is about 532.6559843385.

Adding to 151126433 its reverse (334621151), we get a palindrome (485747584).

The spelling of 151126433 in words is "one hundred fifty-one million, one hundred twenty-six thousand, four hundred thirty-three".