151139993 has 2 divisors, whose sum is σ = 151139994. Its totient is φ = 151139992.

The previous prime is 151139987. The next prime is 151140001. The reversal of 151139993 is 399931151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 146700544 + 4439449 = 12112^2 + 2107^2 .

It is an emirp because it is prime and its reverse (399931151) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 151139993 - 2¹⁶ = 151074457 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 151139993.

It is not a weakly prime, because it can be changed into another prime (151139953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75569996 + 75569997.

It is an arithmetic number, because the mean of its divisors is an integer number (75569997).

Almost surely, 2^151139993 is an apocalyptic number.

It is an amenable number.

151139993 is a deficient number, since it is larger than the sum of its proper divisors (1).

151139993 is an equidigital number, since it uses as much as digits as its factorization.

151139993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 32805, while the sum is 41.

The square root of 151139993 is about 12293.9006421884. The cubic root of 151139993 is about 532.6719149272.

The spelling of 151139993 in words is "one hundred fifty-one million, one hundred thirty-nine thousand, nine hundred ninety-three".