Base | Representation |
---|---|
bin | 1000110011000010101… |
… | …1011101011000000010 |
3 | 112110010020121200011021 |
4 | 2030300223131120002 |
5 | 4434013440213432 |
6 | 153233310340054 |
7 | 13630255341166 |
oct | 2146053353002 |
9 | 473106550137 |
10 | 151140554242 |
11 | 591099a2467 |
12 | 253607ba62a |
13 | 1133895c022 |
14 | 745b048ca6 |
15 | 3de8cc6697 |
hex | 2330add602 |
151140554242 has 4 divisors (see below), whose sum is σ = 226710831366. Its totient is φ = 75570277120.
The previous prime is 151140554237. The next prime is 151140554333. The reversal of 151140554242 is 242455041151.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 89681681961 + 61458872281 = 299469^2 + 247909^2 .
It is a junction number, because it is equal to n+sod(n) for n = 151140554198 and 151140554207.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37785138559 + ... + 37785138562.
Almost surely, 2151140554242 is an apocalyptic number.
151140554242 is a deficient number, since it is larger than the sum of its proper divisors (75570277124).
151140554242 is an equidigital number, since it uses as much as digits as its factorization.
151140554242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75570277123.
The product of its (nonzero) digits is 32000, while the sum is 34.
Adding to 151140554242 its reverse (242455041151), we get a palindrome (393595595393).
The spelling of 151140554242 in words is "one hundred fifty-one billion, one hundred forty million, five hundred fifty-four thousand, two hundred forty-two".
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