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15114345041 is a prime number
BaseRepresentation
bin11100001001110001…
…01001101001010001
31110000100022021121002
432010320221221101
5221423233020131
610535440511345
71043355545615
oct160470515121
943010267532
1015114345041
116456721154
122b1991b555
13156b443043
14a354ab345
155d6d9e6cb
hex384e29a51

15114345041 has 2 divisors, whose sum is σ = 15114345042. Its totient is φ = 15114345040.

The previous prime is 15114344983. The next prime is 15114345067. The reversal of 15114345041 is 14054341151.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14854490641 + 259854400 = 121879^2 + 16120^2 .

It is a cyclic number.

It is not a de Polignac number, because 15114345041 - 26 = 15114344977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15114344995 and 15114345013.

It is not a weakly prime, because it can be changed into another prime (15114345641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7557172520 + 7557172521.

It is an arithmetic number, because the mean of its divisors is an integer number (7557172521).

Almost surely, 215114345041 is an apocalyptic number.

It is an amenable number.

15114345041 is a deficient number, since it is larger than the sum of its proper divisors (1).

15114345041 is an equidigital number, since it uses as much as digits as its factorization.

15114345041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 15114345041 its reverse (14054341151), we get a palindrome (29168686192).

The spelling of 15114345041 in words is "fifteen billion, one hundred fourteen million, three hundred forty-five thousand, forty-one".