Base | Representation |
---|---|
bin | 1000110011000011100… |
… | …1000110100111100011 |
3 | 112110010111100101121101 |
4 | 2030300321012213203 |
5 | 4434020344143133 |
6 | 153233515135231 |
7 | 13630330626163 |
oct | 2146071064743 |
9 | 473114311541 |
10 | 151144131043 |
11 | 59110a157a4 |
12 | 25361a44517 |
13 | 11339612089 |
14 | 745b6da5a3 |
15 | 3de928137d |
hex | 2330e469e3 |
151144131043 has 2 divisors, whose sum is σ = 151144131044. Its totient is φ = 151144131042.
The previous prime is 151144131031. The next prime is 151144131157. The reversal of 151144131043 is 340131441151.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 151144131043 - 213 = 151144122851 is a prime.
It is not a weakly prime, because it can be changed into another prime (151144132043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75572065521 + 75572065522.
It is an arithmetic number, because the mean of its divisors is an integer number (75572065522).
Almost surely, 2151144131043 is an apocalyptic number.
151144131043 is a deficient number, since it is larger than the sum of its proper divisors (1).
151144131043 is an equidigital number, since it uses as much as digits as its factorization.
151144131043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 151144131043 its reverse (340131441151), we get a palindrome (491275572194).
The spelling of 151144131043 in words is "one hundred fifty-one billion, one hundred forty-four million, one hundred thirty-one thousand, forty-three".
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