Base | Representation |
---|---|
bin | 1000110011000011111… |
… | …0011110111000011111 |
3 | 112110010121000000220121 |
4 | 2030300332132320133 |
5 | 4434021224304101 |
6 | 153234005255411 |
7 | 13630345621243 |
oct | 2146076367037 |
9 | 473117000817 |
10 | 151145541151 |
11 | 59111799180 |
12 | 25362404567 |
13 | 113399b6b67 |
14 | 745b986423 |
15 | 3de945e0a1 |
hex | 2330f9ee1f |
151145541151 has 4 divisors (see below), whose sum is σ = 164886044904. Its totient is φ = 137405037400.
The previous prime is 151145541097. The next prime is 151145541229.
151145541151 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 151145541151 - 27 = 151145541023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (151145541551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6870251860 + ... + 6870251881.
It is an arithmetic number, because the mean of its divisors is an integer number (41221511226).
Almost surely, 2151145541151 is an apocalyptic number.
151145541151 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
151145541151 is a deficient number, since it is larger than the sum of its proper divisors (13740503753).
151145541151 is a wasteful number, since it uses less digits than its factorization.
151145541151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13740503752.
The product of its digits is 10000, while the sum is 34.
It can be divided in two parts, 151145 and 541151, that added together give a palindrome (692296).
The spelling of 151145541151 in words is "one hundred fifty-one billion, one hundred forty-five million, five hundred forty-one thousand, one hundred fifty-one".
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