15121125133 has 4 divisors (see below), whose sum is σ = 16010603100. Its totient is φ = 14231647168.

The previous prime is 15121125119. The next prime is 15121125179. The reversal of 15121125133 is 33152112151.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33152112151 = 769 ⋅43110679.

It can be written as a sum of positive squares in 2 ways, for example, as 9513661444 + 5607463689 = 97538^2 + 74883^2 .

It is a cyclic number.

It is not a de Polignac number, because 15121125133 - 2⁵ = 15121125101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 15121125098 and 15121125107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15121125193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 444738958 + ... + 444738991.

It is an arithmetic number, because the mean of its divisors is an integer number (4002650775).

Almost surely, 2^15121125133 is an apocalyptic number.

It is an amenable number.

15121125133 is a deficient number, since it is larger than the sum of its proper divisors (889477967).

15121125133 is an equidigital number, since it uses as much as digits as its factorization.

15121125133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 889477966.

The product of its digits is 900, while the sum is 25.

Adding to 15121125133 its reverse (33152112151), we get a palindrome (48273237284).

The spelling of 15121125133 in words is "fifteen billion, one hundred twenty-one million, one hundred twenty-five thousand, one hundred thirty-three".