Base | Representation |
---|---|
bin | 1101110000001010101000… |
… | …1011011101100000101110 |
3 | 1222112120022020122122201111 |
4 | 3130002222023131200232 |
5 | 3440221043320404402 |
6 | 52054320020302234 |
7 | 3120315642256264 |
oct | 334025213354056 |
9 | 58476266578644 |
10 | 15121140013102 |
11 | 48aa92636a392 |
12 | 18426b324197a |
13 | 858bc06572c6 |
14 | 3a3c1d3b4434 |
15 | 1b35077569d7 |
hex | dc0aa2dd82e |
15121140013102 has 4 divisors (see below), whose sum is σ = 22681710019656. Its totient is φ = 7560570006550.
The previous prime is 15121140013019. The next prime is 15121140013103. The reversal of 15121140013102 is 20131004112151.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15121140013103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3780285003274 + ... + 3780285003277.
It is an arithmetic number, because the mean of its divisors is an integer number (5670427504914).
Almost surely, 215121140013102 is an apocalyptic number.
15121140013102 is a deficient number, since it is larger than the sum of its proper divisors (7560570006554).
15121140013102 is an equidigital number, since it uses as much as digits as its factorization.
15121140013102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7560570006553.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 15121140013102 its reverse (20131004112151), we get a palindrome (35252144125253).
The spelling of 15121140013102 in words is "fifteen trillion, one hundred twenty-one billion, one hundred forty million, thirteen thousand, one hundred two".
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