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15125633232449 is a prime number
BaseRepresentation
bin1101110000011011010111…
…1111101110111001000001
31222112222220101102211220212
43130012311333232321001
53440304244101414244
652100341525443505
73120535202066165
oct334066577567101
958488811384825
1015125633232449
1149018216a9603
121843547b70595
138594584c868c
143a4128036ca5
151b36bbe55d9e
hexdc1b5feee41

15125633232449 has 2 divisors, whose sum is σ = 15125633232450. Its totient is φ = 15125633232448.

The previous prime is 15125633232407. The next prime is 15125633232467. The reversal of 15125633232449 is 94423233652151.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14170195406224 + 955437826225 = 3764332^2 + 977465^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15125633232449 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15125633232397 and 15125633232406.

It is not a weakly prime, because it can be changed into another prime (15125633232499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7562816616224 + 7562816616225.

It is an arithmetic number, because the mean of its divisors is an integer number (7562816616225).

Almost surely, 215125633232449 is an apocalyptic number.

It is an amenable number.

15125633232449 is a deficient number, since it is larger than the sum of its proper divisors (1).

15125633232449 is an equidigital number, since it uses as much as digits as its factorization.

15125633232449 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4665600, while the sum is 50.

The spelling of 15125633232449 in words is "fifteen trillion, one hundred twenty-five billion, six hundred thirty-three million, two hundred thirty-two thousand, four hundred forty-nine".