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151300921461 = 350433640487
BaseRepresentation
bin1000110011101000111…
…1001101100001110101
3112110112102101011121220
42030322033031201311
54434331013441321
6153301235500553
713634243420124
oct2147217154165
9473472334556
10151300921461
1159191475758
12253a6457759
1311362c4a981
147474471abb
153e07e029c6
hex233a3cd875

151300921461 has 4 divisors (see below), whose sum is σ = 201734561952. Its totient is φ = 100867280972.

The previous prime is 151300921357. The next prime is 151300921469. The reversal of 151300921461 is 164129003151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 164129003151 = 354709667717.

It is a cyclic number.

It is not a de Polignac number, because 151300921461 - 227 = 151166703733 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (151300921469) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25216820241 + ... + 25216820246.

It is an arithmetic number, because the mean of its divisors is an integer number (50433640488).

Almost surely, 2151300921461 is an apocalyptic number.

It is an amenable number.

151300921461 is a deficient number, since it is larger than the sum of its proper divisors (50433640491).

151300921461 is an equidigital number, since it uses as much as digits as its factorization.

151300921461 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50433640490.

The product of its (nonzero) digits is 6480, while the sum is 33.

The spelling of 151300921461 in words is "one hundred fifty-one billion, three hundred million, nine hundred twenty-one thousand, four hundred sixty-one".

Divisors: 1 3 50433640487 151300921461