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1513094113 is a prime number
BaseRepresentation
bin101101000101111…
…1111101111100001
310220110011010220201
41122023333233201
511044323002423
6410050505201
752332042046
oct13213775741
93813133821
101513094113
11707114003
12362895201
131b162827b
14104d511cd
158cc842ad
hex5a2ffbe1

1513094113 has 2 divisors, whose sum is σ = 1513094114. Its totient is φ = 1513094112.

The previous prime is 1513094101. The next prime is 1513094153. The reversal of 1513094113 is 3114903151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1478248704 + 34845409 = 38448^2 + 5903^2 .

It is a cyclic number.

It is not a de Polignac number, because 1513094113 - 213 = 1513085921 is a prime.

It is not a weakly prime, because it can be changed into another prime (1513094153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 756547056 + 756547057.

It is an arithmetic number, because the mean of its divisors is an integer number (756547057).

Almost surely, 21513094113 is an apocalyptic number.

It is an amenable number.

1513094113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1513094113 is an equidigital number, since it uses as much as digits as its factorization.

1513094113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 28.

The square root of 1513094113 is about 38898.5104213516. The cubic root of 1513094113 is about 1148.0354898541.

Adding to 1513094113 its reverse (3114903151), we get a palindrome (4627997264).

The spelling of 1513094113 in words is "one billion, five hundred thirteen million, ninety-four thousand, one hundred thirteen".