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15132676450753 is a prime number
BaseRepresentation
bin1101110000110101100111…
…0011011110100111000001
31222120200002020111102002001
43130031121303132213001
53440413210132411003
652103504450224001
73121204554336301
oct334153163364701
958520066442061
1015132676450753
114904806391784
121844992885001
1385a00b753c84
143a45d5603601
151b398045a61d
hexdc359cde9c1

15132676450753 has 2 divisors, whose sum is σ = 15132676450754. Its totient is φ = 15132676450752.

The previous prime is 15132676450739. The next prime is 15132676450789. The reversal of 15132676450753 is 35705467623151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15132317840784 + 358609969 = 3890028^2 + 18937^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15132676450753 is a prime.

It is a super-3 number, since 3×151326764507533 (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 15132676450694 and 15132676450703.

It is not a weakly prime, because it can be changed into another prime (15132676450553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7566338225376 + 7566338225377.

It is an arithmetic number, because the mean of its divisors is an integer number (7566338225377).

Almost surely, 215132676450753 is an apocalyptic number.

It is an amenable number.

15132676450753 is a deficient number, since it is larger than the sum of its proper divisors (1).

15132676450753 is an equidigital number, since it uses as much as digits as its factorization.

15132676450753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15876000, while the sum is 55.

The spelling of 15132676450753 in words is "fifteen trillion, one hundred thirty-two billion, six hundred seventy-six million, four hundred fifty thousand, seven hundred fifty-three".