Base | Representation |
---|---|
bin | 1000110011110101011… |
… | …1001101011110011001 |
3 | 112110200002000211010011 |
4 | 2030331113031132121 |
5 | 4434432424200131 |
6 | 153310351321521 |
7 | 13635451151125 |
oct | 2147527153631 |
9 | 473602024104 |
10 | 151353350041 |
11 | 59209025063 |
12 | 253bbb202a1 |
13 | 11370a765ba |
14 | 747b3dc585 |
15 | 3e0c80c0b1 |
hex | 233d5cd799 |
151353350041 has 2 divisors, whose sum is σ = 151353350042. Its totient is φ = 151353350040.
The previous prime is 151353349909. The next prime is 151353350047. The reversal of 151353350041 is 140053353151.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 151317888016 + 35462025 = 388996^2 + 5955^2 .
It is a cyclic number.
It is not a de Polignac number, because 151353350041 - 217 = 151353218969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 151353349985 and 151353350012.
It is not a weakly prime, because it can be changed into another prime (151353350047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75676675020 + 75676675021.
It is an arithmetic number, because the mean of its divisors is an integer number (75676675021).
Almost surely, 2151353350041 is an apocalyptic number.
It is an amenable number.
151353350041 is a deficient number, since it is larger than the sum of its proper divisors (1).
151353350041 is an equidigital number, since it uses as much as digits as its factorization.
151353350041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 151353350041 in words is "one hundred fifty-one billion, three hundred fifty-three million, three hundred fifty thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •