Base | Representation |
---|---|
bin | 10110000001100101110… |
… | …001101001111111001010 |
3 | 12100200200221000101111121 |
4 | 112001211301221333022 |
5 | 144244210204112132 |
6 | 3115150413145454 |
7 | 214230555523126 |
oct | 26014561517712 |
9 | 5320627011447 |
10 | 1513536004042 |
11 | 533983686597 |
12 | 20540018b28a |
13 | ac95886815a |
14 | 53381280586 |
15 | 295858c7497 |
hex | 16065c69fca |
1513536004042 has 4 divisors (see below), whose sum is σ = 2270304006066. Its totient is φ = 756768002020.
The previous prime is 1513536004009. The next prime is 1513536004081. The reversal of 1513536004042 is 2404006353151.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1373398830241 + 140137173801 = 1171921^2 + 374349^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1513536003989 and 1513536004007.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 378384001009 + ... + 378384001012.
Almost surely, 21513536004042 is an apocalyptic number.
1513536004042 is a deficient number, since it is larger than the sum of its proper divisors (756768002024).
1513536004042 is an equidigital number, since it uses as much as digits as its factorization.
1513536004042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 756768002023.
The product of its (nonzero) digits is 43200, while the sum is 34.
The spelling of 1513536004042 in words is "one trillion, five hundred thirteen billion, five hundred thirty-six million, four thousand, forty-two".
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