Base | Representation |
---|---|
bin | 11100001100101101… |
… | …01100111111000111 |
3 | 1110002001200220012110 |
4 | 32012112230333013 |
5 | 222001041002023 |
6 | 10542121152103 |
7 | 1044105244002 |
oct | 160626547707 |
9 | 43061626173 |
10 | 15139000263 |
11 | 6469630a72 |
12 | 2b2602b633 |
13 | 157359632a |
14 | a38888539 |
15 | 5d911ea93 |
hex | 3865acfc7 |
15139000263 has 4 divisors (see below), whose sum is σ = 20185333688. Its totient is φ = 10092666840.
The previous prime is 15139000241. The next prime is 15139000267. The reversal of 15139000263 is 36200093151.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 15139000263 - 214 = 15138983879 is a prime.
It is a super-2 number, since 2×151390002632 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 15139000263.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15139000267) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2523166708 + ... + 2523166713.
It is an arithmetic number, because the mean of its divisors is an integer number (5046333422).
Almost surely, 215139000263 is an apocalyptic number.
15139000263 is a deficient number, since it is larger than the sum of its proper divisors (5046333425).
15139000263 is an equidigital number, since it uses as much as digits as its factorization.
15139000263 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5046333424.
The product of its (nonzero) digits is 4860, while the sum is 30.
The spelling of 15139000263 in words is "fifteen billion, one hundred thirty-nine million, two hundred sixty-three", and thus it is an aban number.
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