Base | Representation |
---|---|
bin | 10110000010000100101… |
… | …110000000010011110001 |
3 | 12100202001002212020222021 |
4 | 112002010232000103301 |
5 | 144301241103444333 |
6 | 3115314120111441 |
7 | 214246461231562 |
oct | 26020456002361 |
9 | 5322032766867 |
10 | 1514055140593 |
11 | 53411a723566 |
12 | 205526005581 |
13 | aca0c290648 |
14 | 533d01b8169 |
15 | 295b627082d |
hex | 16084b804f1 |
1514055140593 has 2 divisors, whose sum is σ = 1514055140594. Its totient is φ = 1514055140592.
The previous prime is 1514055140569. The next prime is 1514055140627. The reversal of 1514055140593 is 3950415504151.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1133153863009 + 380901277584 = 1064497^2 + 617172^2 .
It is an emirp because it is prime and its reverse (3950415504151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1514055140593 - 25 = 1514055140561 is a prime.
It is not a weakly prime, because it can be changed into another prime (1514055140503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 757027570296 + 757027570297.
It is an arithmetic number, because the mean of its divisors is an integer number (757027570297).
Almost surely, 21514055140593 is an apocalyptic number.
It is an amenable number.
1514055140593 is a deficient number, since it is larger than the sum of its proper divisors (1).
1514055140593 is an equidigital number, since it uses as much as digits as its factorization.
1514055140593 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 270000, while the sum is 43.
The spelling of 1514055140593 in words is "one trillion, five hundred fourteen billion, fifty-five million, one hundred forty thousand, five hundred ninety-three".
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