Base | Representation |
---|---|
bin | 1101110001010101000111… |
… | …1000010011110010100011 |
3 | 1222121110220121210200011111 |
4 | 3130111101320103302203 |
5 | 3441033020124342034 |
6 | 52111423552524151 |
7 | 3121624254452215 |
oct | 334252170236243 |
9 | 58543817720144 |
10 | 15141133434019 |
11 | 490835610544a |
12 | 1846552b50657 |
13 | 85aa5886a498 |
14 | 3a4b988665b5 |
15 | 1b3cc7b23364 |
hex | dc551e13ca3 |
15141133434019 has 2 divisors, whose sum is σ = 15141133434020. Its totient is φ = 15141133434018.
The previous prime is 15141133433981. The next prime is 15141133434043. The reversal of 15141133434019 is 91043433114151.
15141133434019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 15141133434019 - 233 = 15132543499427 is a prime.
It is a super-2 number, since 2×151411334340192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15144133434019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7570566717009 + 7570566717010.
It is an arithmetic number, because the mean of its divisors is an integer number (7570566717010).
Almost surely, 215141133434019 is an apocalyptic number.
15141133434019 is a deficient number, since it is larger than the sum of its proper divisors (1).
15141133434019 is an equidigital number, since it uses as much as digits as its factorization.
15141133434019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 40.
The spelling of 15141133434019 in words is "fifteen trillion, one hundred forty-one billion, one hundred thirty-three million, four hundred thirty-four thousand, nineteen".
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