Base | Representation |
---|---|
bin | 1101110001010101100001… |
… | …1110000111111000100001 |
3 | 1222121111012022212111220211 |
4 | 3130111120132013320201 |
5 | 3441033231431310032 |
6 | 52111442542534121 |
7 | 3121630066363216 |
oct | 334253036077041 |
9 | 58544168774824 |
10 | 15141244010017 |
11 | 490840256a874 |
12 | 1846583b97341 |
13 | 85aa75744a78 |
14 | 3a4ba940bb0d |
15 | 1b3cd26b6747 |
hex | dc558787e21 |
15141244010017 has 2 divisors, whose sum is σ = 15141244010018. Its totient is φ = 15141244010016.
The previous prime is 15141244009973. The next prime is 15141244010021. The reversal of 15141244010017 is 71001044214151.
15141244010017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12707506728081 + 2433737281936 = 3564759^2 + 1560044^2 .
It is a cyclic number.
It is not a de Polignac number, because 15141244010017 - 211 = 15141244007969 is a prime.
It is not a weakly prime, because it can be changed into another prime (15141244010027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7570622005008 + 7570622005009.
It is an arithmetic number, because the mean of its divisors is an integer number (7570622005009).
Almost surely, 215141244010017 is an apocalyptic number.
It is an amenable number.
15141244010017 is a deficient number, since it is larger than the sum of its proper divisors (1).
15141244010017 is an equidigital number, since it uses as much as digits as its factorization.
15141244010017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4480, while the sum is 31.
Adding to 15141244010017 its reverse (71001044214151), we get a palindrome (86142288224168).
The spelling of 15141244010017 in words is "fifteen trillion, one hundred forty-one billion, two hundred forty-four million, ten thousand, seventeen".
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