Base | Representation |
---|---|
bin | 1000110100000011111… |
… | …1111111111110101001 |
3 | 112110211022212011200101 |
4 | 2031000333333332221 |
5 | 4440044034434223 |
6 | 153320411305401 |
7 | 13640121642346 |
oct | 2150077777651 |
9 | 473738764611 |
10 | 151414374313 |
11 | 5923a515544 |
12 | 2541844b261 |
13 | 113805c1837 |
14 | 74855657cd |
15 | 3e12d634ad |
hex | 2340ffffa9 |
151414374313 has 2 divisors, whose sum is σ = 151414374314. Its totient is φ = 151414374312.
The previous prime is 151414374259. The next prime is 151414374323. The reversal of 151414374313 is 313473414151.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 151012291609 + 402082704 = 388603^2 + 20052^2 .
It is an emirp because it is prime and its reverse (313473414151) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-151414374313 is a prime.
It is not a weakly prime, because it can be changed into another prime (151414374323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75707187156 + 75707187157.
It is an arithmetic number, because the mean of its divisors is an integer number (75707187157).
Almost surely, 2151414374313 is an apocalyptic number.
It is an amenable number.
151414374313 is a deficient number, since it is larger than the sum of its proper divisors (1).
151414374313 is an equidigital number, since it uses as much as digits as its factorization.
151414374313 is an evil number, because the sum of its binary digits is even.
The product of its digits is 60480, while the sum is 37.
Adding to 151414374313 its reverse (313473414151), we get a palindrome (464887788464).
The spelling of 151414374313 in words is "one hundred fifty-one billion, four hundred fourteen million, three hundred seventy-four thousand, three hundred thirteen".
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