Base | Representation |
---|---|
bin | 11100001101001111… |
… | …00101010001101100 |
3 | 1110002101000200222111 |
4 | 32012213211101230 |
5 | 222003204101012 |
6 | 10542400053404 |
7 | 1044160663333 |
oct | 160647452154 |
9 | 43071020874 |
10 | 15143425132 |
11 | 6471083490 |
12 | 2b27604264 |
13 | 15744853b4 |
14 | a392bad1a |
15 | 5d96e5ba7 |
hex | 3869e546c |
15143425132 has 24 divisors (see below), whose sum is σ = 28914197760. Its totient is φ = 6882417360.
The previous prime is 15143425097. The next prime is 15143425133. The reversal of 15143425132 is 23152434151.
15143425132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 15143425094 and 15143425103.
It is not an unprimeable number, because it can be changed into a prime (15143425133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 367969 + ... + 407047.
It is an arithmetic number, because the mean of its divisors is an integer number (1204758240).
Almost surely, 215143425132 is an apocalyptic number.
It is an amenable number.
15143425132 is a deficient number, since it is larger than the sum of its proper divisors (13770772628).
15143425132 is a wasteful number, since it uses less digits than its factorization.
15143425132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47901 (or 47899 counting only the distinct ones).
The product of its digits is 14400, while the sum is 31.
Adding to 15143425132 its reverse (23152434151), we get a palindrome (38295859283).
The spelling of 15143425132 in words is "fifteen billion, one hundred forty-three million, four hundred twenty-five thousand, one hundred thirty-two".
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