Base | Representation |
---|---|
bin | 11100001101010100… |
… | …10100100100000011 |
3 | 1110002102101011212011 |
4 | 32012222110210003 |
5 | 222003400034412 |
6 | 10542423313351 |
7 | 1044200043502 |
oct | 160652244403 |
9 | 43072334764 |
10 | 15144143107 |
11 | 6471523955 |
12 | 2b278ab857 |
13 | 1574677132 |
14 | a39426839 |
15 | 5d97d87a7 |
hex | 386a94903 |
15144143107 has 2 divisors, whose sum is σ = 15144143108. Its totient is φ = 15144143106.
The previous prime is 15144143089. The next prime is 15144143171. The reversal of 15144143107 is 70134144151.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15144143107 is a prime.
It is a super-2 number, since 2×151441431072 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15144144107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7572071553 + 7572071554.
It is an arithmetic number, because the mean of its divisors is an integer number (7572071554).
Almost surely, 215144143107 is an apocalyptic number.
15144143107 is a deficient number, since it is larger than the sum of its proper divisors (1).
15144143107 is an equidigital number, since it uses as much as digits as its factorization.
15144143107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 15144143107 its reverse (70134144151), we get a palindrome (85278287258).
The spelling of 15144143107 in words is "fifteen billion, one hundred forty-four million, one hundred forty-three thousand, one hundred seven".
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