Base | Representation |
---|---|
bin | 1000110100110001110… |
… | …0010010101000101111 |
3 | 112111022201002001021221 |
4 | 2031030130102220233 |
5 | 4440442210341033 |
6 | 153351430004211 |
7 | 13644642425446 |
oct | 2151434225057 |
9 | 474281061257 |
10 | 151606340143 |
11 | 59328910295 |
12 | 254707a6667 |
13 | 113b12c4c9b |
14 | 74a2c55d5d |
15 | 3e24b3212d |
hex | 234c712a2f |
151606340143 has 4 divisors (see below), whose sum is σ = 151779210280. Its totient is φ = 151433470008.
The previous prime is 151606340029. The next prime is 151606340177. The reversal of 151606340143 is 341043606151.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 341043606151 = 331 ⋅1030343221.
It is a cyclic number.
It is not a de Polignac number, because 151606340143 - 229 = 151069469231 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 151606340099 and 151606340108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (151606340443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86433753 + ... + 86435506.
It is an arithmetic number, because the mean of its divisors is an integer number (37944802570).
Almost surely, 2151606340143 is an apocalyptic number.
151606340143 is a deficient number, since it is larger than the sum of its proper divisors (172870137).
151606340143 is an equidigital number, since it uses as much as digits as its factorization.
151606340143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 172870136.
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 151606340143 its reverse (341043606151), we get a palindrome (492649946294).
The spelling of 151606340143 in words is "one hundred fifty-one billion, six hundred six million, three hundred forty thousand, one hundred forty-three".
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