Base | Representation |
---|---|
bin | 11100010100000000… |
… | …10111010011001101 |
3 | 1110020022221212100021 |
4 | 32022000113103031 |
5 | 222112231100013 |
6 | 10552150102141 |
7 | 1045451006542 |
oct | 161200272315 |
9 | 43208855307 |
10 | 15200253133 |
11 | 64a016817a |
12 | 2b4264a951 |
13 | 1583191630 |
14 | a42a70bc9 |
15 | 5de6bda8d |
hex | 38a0174cd |
15200253133 has 8 divisors (see below), whose sum is σ = 17081221248. Its totient is φ = 13420959024.
The previous prime is 15200253091. The next prime is 15200253139. The reversal of 15200253133 is 33135200251.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15200253133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15200253098 and 15200253107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15200253139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25418185 + ... + 25418782.
It is an arithmetic number, because the mean of its divisors is an integer number (2135152656).
Almost surely, 215200253133 is an apocalyptic number.
15200253133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
15200253133 is a deficient number, since it is larger than the sum of its proper divisors (1880968115).
15200253133 is a wasteful number, since it uses less digits than its factorization.
15200253133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50837003.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 15200253133 its reverse (33135200251), we get a palindrome (48335453384).
The spelling of 15200253133 in words is "fifteen billion, two hundred million, two hundred fifty-three thousand, one hundred thirty-three".
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