Base | Representation |
---|---|
bin | 10110000111101111100… |
… | …001101010010011001011 |
3 | 12101022202022102111011101 |
4 | 112013233201222103023 |
5 | 144401222330042443 |
6 | 3122202115242231 |
7 | 214553352044056 |
oct | 26075741522313 |
9 | 5338668374141 |
10 | 1520142034123 |
11 | 536763603789 |
12 | 2067445a9377 |
13 | b046c3613ab |
14 | 5380a765a9d |
15 | 2982081e84d |
hex | 161ef86a4cb |
1520142034123 has 2 divisors, whose sum is σ = 1520142034124. Its totient is φ = 1520142034122.
The previous prime is 1520142034111. The next prime is 1520142034133. The reversal of 1520142034123 is 3214302410251.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1520142034123 - 29 = 1520142033611 is a prime.
It is a super-2 number, since 2×15201420341232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1520142034091 and 1520142034100.
It is not a weakly prime, because it can be changed into another prime (1520142034133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 760071017061 + 760071017062.
It is an arithmetic number, because the mean of its divisors is an integer number (760071017062).
Almost surely, 21520142034123 is an apocalyptic number.
1520142034123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1520142034123 is an equidigital number, since it uses as much as digits as its factorization.
1520142034123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 1520142034123 its reverse (3214302410251), we get a palindrome (4734444444374).
The spelling of 1520142034123 in words is "one trillion, five hundred twenty billion, one hundred forty-two million, thirty-four thousand, one hundred twenty-three".
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