Base | Representation |
---|---|
bin | 11100010100010101… |
… | …11001000110111111 |
3 | 1110020112011002020121 |
4 | 32022022321012333 |
5 | 222113432404210 |
6 | 10552325155411 |
7 | 1045513323136 |
oct | 161212710677 |
9 | 43215132217 |
10 | 15203013055 |
11 | 64a17827aa |
12 | 2b4355bb67 |
13 | 1583919919 |
14 | a4318c91d |
15 | 5dea666da |
hex | 38a2b91bf |
15203013055 has 8 divisors (see below), whose sum is σ = 18279460800. Its totient is φ = 12138513696.
The previous prime is 15203013053. The next prime is 15203013071. The reversal of 15203013055 is 55031030251.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 15203013055 - 21 = 15203013053 is a prime.
It is a super-2 number, since 2×152030130552 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15203013053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2984295 + ... + 2989384.
It is an arithmetic number, because the mean of its divisors is an integer number (2284932600).
Almost surely, 215203013055 is an apocalyptic number.
15203013055 is a deficient number, since it is larger than the sum of its proper divisors (3076447745).
15203013055 is an equidigital number, since it uses as much as digits as its factorization.
15203013055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5974193.
The product of its (nonzero) digits is 2250, while the sum is 25.
The spelling of 15203013055 in words is "fifteen billion, two hundred three million, thirteen thousand, fifty-five".
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