Base | Representation |
---|---|
bin | 1000110110011000000… |
… | …1000010001001011111 |
3 | 112112102121102122222020 |
4 | 2031212001002021133 |
5 | 4442332030333320 |
6 | 153502154151223 |
7 | 13661402411565 |
oct | 2154601021137 |
9 | 475377378866 |
10 | 152035402335 |
11 | 59529026043 |
12 | 25570422513 |
13 | 1144c17073b |
14 | 7503c23a35 |
15 | 3e4c636940 |
hex | 236604225f |
152035402335 has 32 divisors (see below), whose sum is σ = 243904224000. Its totient is φ = 80869909248.
The previous prime is 152035402331. The next prime is 152035402367. The reversal of 152035402335 is 533204530251.
It is not a de Polignac number, because 152035402335 - 22 = 152035402331 is a prime.
It is a super-2 number, since 2×1520354023352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 152035402296 and 152035402305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (152035402331) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13115412 + ... + 13126998.
It is an arithmetic number, because the mean of its divisors is an integer number (7622007000).
Almost surely, 2152035402335 is an apocalyptic number.
152035402335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
152035402335 is a deficient number, since it is larger than the sum of its proper divisors (91868821665).
152035402335 is a wasteful number, since it uses less digits than its factorization.
152035402335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13847.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 152035402335 its reverse (533204530251), we get a palindrome (685239932586).
The spelling of 152035402335 in words is "one hundred fifty-two billion, thirty-five million, four hundred two thousand, three hundred thirty-five".
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