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1520422018 = 21900140009
BaseRepresentation
bin101101010011111…
…1100110010000010
310220221221102220121
41122213330302002
511103212001033
6410511530454
752451242153
oct13247746202
93827842817
101520422018
11710269625
12365229a2a
131b2cc27cb
14105cdb92a
158d73062d
hex5a9fcc82

1520422018 has 8 divisors (see below), whose sum is σ = 2280810060. Its totient is φ = 760152000.

The previous prime is 1520422003. The next prime is 1520422031. The reversal of 1520422018 is 8102240251.

It can be written as a sum of positive squares in 2 ways, for example, as 1468192489 + 52229529 = 38317^2 + 7227^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×15204220182 = 4623366225638384648, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1520421983 and 1520422001.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17998 + ... + 58006.

Almost surely, 21520422018 is an apocalyptic number.

1520422018 is a deficient number, since it is larger than the sum of its proper divisors (760388042).

1520422018 is a wasteful number, since it uses less digits than its factorization.

1520422018 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59012.

The product of its (nonzero) digits is 1280, while the sum is 25.

The square root of 1520422018 is about 38992.5892702703. The cubic root of 1520422018 is about 1149.8858155060.

Adding to 1520422018 its reverse (8102240251), we get a palindrome (9622662269).

The spelling of 1520422018 in words is "one billion, five hundred twenty million, four hundred twenty-two thousand, eighteen".

Divisors: 1 2 19001 38002 40009 80018 760211009 1520422018