Base | Representation |
---|---|
bin | 1000110110100111100… |
… | …1100001011111101011 |
3 | 112112121011000010101211 |
4 | 2031221321201133223 |
5 | 4443000214324233 |
6 | 153512442253551 |
7 | 13663123164463 |
oct | 2155171413753 |
9 | 475534003354 |
10 | 152100542443 |
11 | 59561877843 |
12 | 2558a1b72b7 |
13 | 1145c7ca195 |
14 | 750c73cba3 |
15 | 3e532025cd |
hex | 2369e617eb |
152100542443 has 2 divisors, whose sum is σ = 152100542444. Its totient is φ = 152100542442.
The previous prime is 152100542423. The next prime is 152100542467. The reversal of 152100542443 is 344245001251.
It is a weak prime.
It is an emirp because it is prime and its reverse (344245001251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 152100542443 - 25 = 152100542411 is a prime.
It is a super-2 number, since 2×1521005424432 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (152100542423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76050271221 + 76050271222.
It is an arithmetic number, because the mean of its divisors is an integer number (76050271222).
Almost surely, 2152100542443 is an apocalyptic number.
152100542443 is a deficient number, since it is larger than the sum of its proper divisors (1).
152100542443 is an equidigital number, since it uses as much as digits as its factorization.
152100542443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 152100542443 its reverse (344245001251), we get a palindrome (496345543694).
The spelling of 152100542443 in words is "one hundred fifty-two billion, one hundred million, five hundred forty-two thousand, four hundred forty-three".
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