152113566301 has 4 divisors (see below), whose sum is σ = 154691762400. Its totient is φ = 149535370204.

The previous prime is 152113566251. The next prime is 152113566329. The reversal of 152113566301 is 103665311251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 103665311251 = 1879 ⋅55170469.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-152113566301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (152113566391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1289097961 + ... + 1289098078.

It is an arithmetic number, because the mean of its divisors is an integer number (38672940600).

Almost surely, 2^152113566301 is an apocalyptic number.

It is an amenable number.

152113566301 is a deficient number, since it is larger than the sum of its proper divisors (2578196099).

152113566301 is an equidigital number, since it uses as much as digits as its factorization.

152113566301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2578196098.

The product of its (nonzero) digits is 16200, while the sum is 34.

Adding to 152113566301 its reverse (103665311251), we get a palindrome (255778877552).

The spelling of 152113566301 in words is "one hundred fifty-two billion, one hundred thirteen million, five hundred sixty-six thousand, three hundred one".