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1521200112121 is a prime number
BaseRepresentation
bin10110001000101110100…
…101111010000111111001
312101102111001101102022101
4112020232211322013321
5144410404212041441
63122455113423401
7214621520415424
oct26105645720771
95342431342271
101521200112121
11537156895408
1220699aa0ab61
13b05aa624751
14538ab0b09bb
1529883674231
hex1622e97a1f9

1521200112121 has 2 divisors, whose sum is σ = 1521200112122. Its totient is φ = 1521200112120.

The previous prime is 1521200112097. The next prime is 1521200112167. The reversal of 1521200112121 is 1212110021251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1496499589225 + 24700522896 = 1223315^2 + 157164^2 .

It is an emirp because it is prime and its reverse (1212110021251) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1521200112121 - 219 = 1521199587833 is a prime.

It is a super-2 number, since 2×15212001121212 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1521201112121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 760600056060 + 760600056061.

It is an arithmetic number, because the mean of its divisors is an integer number (760600056061).

Almost surely, 21521200112121 is an apocalyptic number.

It is an amenable number.

1521200112121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1521200112121 is an equidigital number, since it uses as much as digits as its factorization.

1521200112121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 19.

Adding to 1521200112121 its reverse (1212110021251), we get a palindrome (2733310133372).

The spelling of 1521200112121 in words is "one trillion, five hundred twenty-one billion, two hundred million, one hundred twelve thousand, one hundred twenty-one".