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152121402353 is a prime number
BaseRepresentation
bin1000110110101100100…
…1000110001111110001
3112112122121020220211002
42031223021012033301
54443021034333403
6153514505331345
713663465404524
oct2155311061761
9475577226732
10152121402353
1159572625138
1225595196b55
1311463c21b1b
14751140cbbb
153e54e73188
hex236b2463f1

152121402353 has 2 divisors, whose sum is σ = 152121402354. Its totient is φ = 152121402352.

The previous prime is 152121402337. The next prime is 152121402409. The reversal of 152121402353 is 353204121251.

152121402353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125335824784 + 26785577569 = 354028^2 + 163663^2 .

It is a cyclic number.

It is not a de Polignac number, because 152121402353 - 24 = 152121402337 is a prime.

It is not a weakly prime, because it can be changed into another prime (152121402553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76060701176 + 76060701177.

It is an arithmetic number, because the mean of its divisors is an integer number (76060701177).

Almost surely, 2152121402353 is an apocalyptic number.

It is an amenable number.

152121402353 is a deficient number, since it is larger than the sum of its proper divisors (1).

152121402353 is an equidigital number, since it uses as much as digits as its factorization.

152121402353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 29.

The spelling of 152121402353 in words is "one hundred fifty-two billion, one hundred twenty-one million, four hundred two thousand, three hundred fifty-three".