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152121402841 is a prime number
BaseRepresentation
bin1000110110101100100…
…1000110010111011001
3112112122121020221111011
42031223021012113121
54443021034342331
6153514505333521
713663465406122
oct2155311062731
9475577227434
10152121402841
1159572625541
12255951972a1
1311463c22105
14751140d049
153e54e733b1
hex236b2465d9

152121402841 has 2 divisors, whose sum is σ = 152121402842. Its totient is φ = 152121402840.

The previous prime is 152121402817. The next prime is 152121402847. The reversal of 152121402841 is 148204121251.

152121402841 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 151966649241 + 154753600 = 389829^2 + 12440^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152121402841 is a prime.

It is not a weakly prime, because it can be changed into another prime (152121402847) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76060701420 + 76060701421.

It is an arithmetic number, because the mean of its divisors is an integer number (76060701421).

Almost surely, 2152121402841 is an apocalyptic number.

It is an amenable number.

152121402841 is a deficient number, since it is larger than the sum of its proper divisors (1).

152121402841 is an equidigital number, since it uses as much as digits as its factorization.

152121402841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5120, while the sum is 31.

The spelling of 152121402841 in words is "one hundred fifty-two billion, one hundred twenty-one million, four hundred two thousand, eight hundred forty-one".