152125333 has 4 divisors (see below), whose sum is σ = 161073900. Its totient is φ = 143176768.

The previous prime is 152125321. The next prime is 152125349. The reversal of 152125333 is 333521251.

152125333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 333521251 = 7 ⋅47645893.

It can be written as a sum of positive squares in 2 ways, for example, as 71520849 + 80604484 = 8457^2 + 8978^2 .

It is a cyclic number.

It is not a de Polignac number, because 152125333 - 2²¹ = 150028181 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 152125298 and 152125307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (152125433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4474258 + ... + 4474291.

It is an arithmetic number, because the mean of its divisors is an integer number (40268475).

Almost surely, 2^152125333 is an apocalyptic number.

It is an amenable number.

152125333 is a deficient number, since it is larger than the sum of its proper divisors (8948567).

152125333 is an equidigital number, since it uses as much as digits as its factorization.

152125333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8948566.

The product of its digits is 2700, while the sum is 25.

The square root of 152125333 is about 12333.9098829203. The cubic root of 152125333 is about 533.8269731235.

Adding to 152125333 its reverse (333521251), we get a palindrome (485646584).

The spelling of 152125333 in words is "one hundred fifty-two million, one hundred twenty-five thousand, three hundred thirty-three".