Base | Representation |
---|---|
bin | 1101110101100000111001… |
… | …1111111101110011000100 |
3 | 1222212100110100012200010101 |
4 | 3131120032133331303010 |
5 | 3443222224430014134 |
6 | 52204432544133444 |
7 | 3130050516335230 |
oct | 335301637756304 |
9 | 58770410180111 |
10 | 15213017423044 |
11 | 4935893807341 |
12 | 1858474907284 |
13 | 864773400b2c |
14 | 3a84577795c0 |
15 | 1b5ad382ce14 |
hex | dd60e7fdcc4 |
15213017423044 has 24 divisors (see below), whose sum is σ = 30427597608128. Its totient is φ = 6519529732320.
The previous prime is 15213017423017. The next prime is 15213017423063. The reversal of 15213017423044 is 44032471031251.
It is a super-2 number, since 2×152130174230442 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 15213017422994 and 15213017423012.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13397967 + ... + 14489014.
Almost surely, 215213017423044 is an apocalyptic number.
15213017423044 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
15213017423044 is an abundant number, since it is smaller than the sum of its proper divisors (15214580185084).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
15213017423044 is a wasteful number, since it uses less digits than its factorization.
15213017423044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27906475 (or 27906473 counting only the distinct ones).
The product of its (nonzero) digits is 80640, while the sum is 37.
Adding to 15213017423044 its reverse (44032471031251), we get a palindrome (59245488454295).
The spelling of 15213017423044 in words is "fifteen trillion, two hundred thirteen billion, seventeen million, four hundred twenty-three thousand, forty-four".
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