Base | Representation |
---|---|
bin | 11100010101101101… |
… | …10100111011000001 |
3 | 1110021022211012212001 |
4 | 32022312310323001 |
5 | 222124404431431 |
6 | 10553420104001 |
7 | 1046013242011 |
oct | 161266647301 |
9 | 43238735761 |
10 | 15214530241 |
11 | 64a8229839 |
12 | 2b47395001 |
13 | 158611cc21 |
14 | a44909c41 |
15 | 5e0a8de61 |
hex | 38adb4ec1 |
15214530241 has 2 divisors, whose sum is σ = 15214530242. Its totient is φ = 15214530240.
The previous prime is 15214530211. The next prime is 15214530263. The reversal of 15214530241 is 14203541251.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9619490241 + 5595040000 = 98079^2 + 74800^2 .
It is a cyclic number.
It is not a de Polignac number, because 15214530241 - 223 = 15206141633 is a prime.
It is a super-3 number, since 3×152145302413 (a number of 32 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (15214530211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7607265120 + 7607265121.
It is an arithmetic number, because the mean of its divisors is an integer number (7607265121).
Almost surely, 215214530241 is an apocalyptic number.
It is an amenable number.
15214530241 is a deficient number, since it is larger than the sum of its proper divisors (1).
15214530241 is an equidigital number, since it uses as much as digits as its factorization.
15214530241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 28.
The spelling of 15214530241 in words is "fifteen billion, two hundred fourteen million, five hundred thirty thousand, two hundred forty-one".
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