15216121344041 has 2 divisors, whose sum is σ = 15216121344042. Its totient is φ = 15216121344040.

The previous prime is 15216121343999. The next prime is 15216121344059. The reversal of 15216121344041 is 14044312161251.

15216121344041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8900550257641 + 6315571086400 = 2983379^2 + 2513080^2 .

It is a cyclic number.

It is not a de Polignac number, because 15216121344041 - 2³⁰ = 15215047602217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15216121343992 and 15216121344010.

It is not a weakly prime, because it can be changed into another prime (15216121344841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7608060672020 + 7608060672021.

It is an arithmetic number, because the mean of its divisors is an integer number (7608060672021).

Almost surely, 2^{15216121344041} is an apocalyptic number.

It is an amenable number.

15216121344041 is a deficient number, since it is larger than the sum of its proper divisors (1).

15216121344041 is an equidigital number, since it uses as much as digits as its factorization.

15216121344041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 35.

The spelling of 15216121344041 in words is "fifteen trillion, two hundred sixteen billion, one hundred twenty-one million, three hundred forty-four thousand, forty-one".