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152301101131 is a prime number
BaseRepresentation
bin1000110111010111011…
…0100110000001001011
3112120010010101120012101
42031311312212001023
54443403040214011
6153544405054231
714001106666624
oct2156566460113
9476103346171
10152301101131
1159655001523
12256253b7377
131149221b86a
14752b228a4b
153e65b1c2c1
hex2375da604b

152301101131 has 2 divisors, whose sum is σ = 152301101132. Its totient is φ = 152301101130.

The previous prime is 152301101119. The next prime is 152301101159. The reversal of 152301101131 is 131101103251.

152301101131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 152301101131 - 27 = 152301101003 is a prime.

It is a super-2 number, since 2×1523011011312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 152301101099 and 152301101108.

It is not a weakly prime, because it can be changed into another prime (152301101171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76150550565 + 76150550566.

It is an arithmetic number, because the mean of its divisors is an integer number (76150550566).

Almost surely, 2152301101131 is an apocalyptic number.

152301101131 is a deficient number, since it is larger than the sum of its proper divisors (1).

152301101131 is an equidigital number, since it uses as much as digits as its factorization.

152301101131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 152301101131 its reverse (131101103251), we get a palindrome (283402204382).

The spelling of 152301101131 in words is "one hundred fifty-two billion, three hundred one million, one hundred one thousand, one hundred thirty-one".