Base | Representation |
---|---|
bin | 11100010111100110… |
… | …00110010101011001 |
3 | 1110022102112221022202 |
4 | 32023303012111121 |
5 | 222142431031301 |
6 | 10555142455545 |
7 | 1046264446022 |
oct | 161363062531 |
9 | 43272487282 |
10 | 15230330201 |
11 | 6506140559 |
12 | 2b507345b5 |
13 | 1589492708 |
14 | a46a5dc49 |
15 | 5e216066b |
hex | 38bcc6559 |
15230330201 has 2 divisors, whose sum is σ = 15230330202. Its totient is φ = 15230330200.
The previous prime is 15230330191. The next prime is 15230330257. The reversal of 15230330201 is 10203303251.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11098411801 + 4131918400 = 105349^2 + 64280^2 .
It is an emirp because it is prime and its reverse (10203303251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 15230330201 - 230 = 14156588377 is a prime.
It is not a weakly prime, because it can be changed into another prime (15230336201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7615165100 + 7615165101.
It is an arithmetic number, because the mean of its divisors is an integer number (7615165101).
Almost surely, 215230330201 is an apocalyptic number.
It is an amenable number.
15230330201 is a deficient number, since it is larger than the sum of its proper divisors (1).
15230330201 is an equidigital number, since it uses as much as digits as its factorization.
15230330201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 20.
Adding to 15230330201 its reverse (10203303251), we get a palindrome (25433633452).
The spelling of 15230330201 in words is "fifteen billion, two hundred thirty million, three hundred thirty thousand, two hundred one".
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