Base | Representation |
---|---|
bin | 1000110111011000011… |
… | …0010010010000011011 |
3 | 112120010102010112200001 |
4 | 2031312012102100123 |
5 | 4443410113330431 |
6 | 153545033153431 |
7 | 14001156651133 |
oct | 2156606222033 |
9 | 476112115601 |
10 | 152305214491 |
11 | 596573609a1 |
12 | 2562685b877 |
13 | 1149302bbc1 |
14 | 752b9b9ac3 |
15 | 3e66180e61 |
hex | 237619241b |
152305214491 has 2 divisors, whose sum is σ = 152305214492. Its totient is φ = 152305214490.
The previous prime is 152305214483. The next prime is 152305214533. The reversal of 152305214491 is 194412503251.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 152305214491 - 23 = 152305214483 is a prime.
It is a super-2 number, since 2×1523052144912 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 152305214491.
It is not a weakly prime, because it can be changed into another prime (152305214401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76152607245 + 76152607246.
It is an arithmetic number, because the mean of its divisors is an integer number (76152607246).
Almost surely, 2152305214491 is an apocalyptic number.
152305214491 is a deficient number, since it is larger than the sum of its proper divisors (1).
152305214491 is an equidigital number, since it uses as much as digits as its factorization.
152305214491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 37.
It can be divided in two parts, 152305 and 214491, that added together give a triangular number (366796 = T856).
The spelling of 152305214491 in words is "one hundred fifty-two billion, three hundred five million, two hundred fourteen thousand, four hundred ninety-one".
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