15231114133 has 4 divisors (see below), whose sum is σ = 15232078060. Its totient is φ = 15230150208.

The previous prime is 15231114089. The next prime is 15231114137. The reversal of 15231114133 is 33141113251.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9193357924 + 6037756209 = 95882^2 + 77703^2 .

It is a cyclic number.

It is not a de Polignac number, because 15231114133 - 2²⁵ = 15197559701 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 15231114098 and 15231114107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15231114137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 457860 + ... + 489997.

It is an arithmetic number, because the mean of its divisors is an integer number (3808019515).

Almost surely, 2^15231114133 is an apocalyptic number.

It is an amenable number.

15231114133 is a deficient number, since it is larger than the sum of its proper divisors (963927).

15231114133 is an equidigital number, since it uses as much as digits as its factorization.

15231114133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 963926.

The product of its digits is 1080, while the sum is 25.

Adding to 15231114133 its reverse (33141113251), we get a palindrome (48372227384).

The spelling of 15231114133 in words is "fifteen billion, two hundred thirty-one million, one hundred fourteen thousand, one hundred thirty-three".