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15231144113 is a prime number
BaseRepresentation
bin11100010111101100…
…01101000010110001
31110022111002021210122
432023312031002301
5222143133102423
610555212140025
71046304405653
oct161366150261
943274067718
1015231144113
116506647009
122b50a67615
1315896b9013
14a46bd26d3
155e22718c8
hex38bd8d0b1

15231144113 has 2 divisors, whose sum is σ = 15231144114. Its totient is φ = 15231144112.

The previous prime is 15231144109. The next prime is 15231144133. The reversal of 15231144113 is 31144113251.

15231144113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14463189169 + 767954944 = 120263^2 + 27712^2 .

It is a cyclic number.

It is not a de Polignac number, because 15231144113 - 22 = 15231144109 is a prime.

It is not a weakly prime, because it can be changed into another prime (15231144133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7615572056 + 7615572057.

It is an arithmetic number, because the mean of its divisors is an integer number (7615572057).

Almost surely, 215231144113 is an apocalyptic number.

It is an amenable number.

15231144113 is a deficient number, since it is larger than the sum of its proper divisors (1).

15231144113 is an equidigital number, since it uses as much as digits as its factorization.

15231144113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 26.

Adding to 15231144113 its reverse (31144113251), we get a palindrome (46375257364).

The spelling of 15231144113 in words is "fifteen billion, two hundred thirty-one million, one hundred forty-four thousand, one hundred thirteen".