Base | Representation |
---|---|
bin | 1000110111011100001… |
… | …1101100101011011111 |
3 | 112120011112102110100202 |
4 | 2031313003230223133 |
5 | 4443423224013003 |
6 | 153550410214115 |
7 | 14001443542052 |
oct | 2156703545337 |
9 | 476145373322 |
10 | 152321313503 |
11 | 59665457367 |
12 | 2563012433b |
13 | 11496477848 |
14 | 752dbaaa99 |
15 | 3e677b1088 |
hex | 23770ecadf |
152321313503 has 4 divisors (see below), whose sum is σ = 160338224760. Its totient is φ = 144304402248.
The previous prime is 152321313481. The next prime is 152321313527. The reversal of 152321313503 is 305313123251.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 152321313503 - 28 = 152321313247 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (152321313563) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4008455600 + ... + 4008455637.
It is an arithmetic number, because the mean of its divisors is an integer number (40084556190).
Almost surely, 2152321313503 is an apocalyptic number.
152321313503 is a deficient number, since it is larger than the sum of its proper divisors (8016911257).
152321313503 is an equidigital number, since it uses as much as digits as its factorization.
152321313503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8016911256.
The product of its (nonzero) digits is 8100, while the sum is 29.
Adding to 152321313503 its reverse (305313123251), we get a palindrome (457634436754).
The spelling of 152321313503 in words is "one hundred fifty-two billion, three hundred twenty-one million, three hundred thirteen thousand, five hundred three".
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