Base | Representation |
---|---|
bin | 1000110111011111000… |
… | …1110110111011100001 |
3 | 112120012101012020021111 |
4 | 2031313301312323201 |
5 | 4443434323222423 |
6 | 153551521423321 |
7 | 14001651440566 |
oct | 2156761667341 |
9 | 476171166244 |
10 | 152333414113 |
11 | 59671271771 |
12 | 2563419ab41 |
13 | 11498b2357a |
14 | 753163a86d |
15 | 3e688a160d |
hex | 2377c76ee1 |
152333414113 has 2 divisors, whose sum is σ = 152333414114. Its totient is φ = 152333414112.
The previous prime is 152333414047. The next prime is 152333414153. The reversal of 152333414113 is 311414333251.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 136240715664 + 16092698449 = 369108^2 + 126857^2 .
It is a cyclic number.
It is not a de Polignac number, because 152333414113 - 225 = 152299859681 is a prime.
It is not a weakly prime, because it can be changed into another prime (152333414153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76166707056 + 76166707057.
It is an arithmetic number, because the mean of its divisors is an integer number (76166707057).
Almost surely, 2152333414113 is an apocalyptic number.
It is an amenable number.
152333414113 is a deficient number, since it is larger than the sum of its proper divisors (1).
152333414113 is an equidigital number, since it uses as much as digits as its factorization.
152333414113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12960, while the sum is 31.
Adding to 152333414113 its reverse (311414333251), we get a palindrome (463747747364).
The spelling of 152333414113 in words is "one hundred fifty-two billion, three hundred thirty-three million, four hundred fourteen thousand, one hundred thirteen".
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